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313310112243403 = 1128482737476673
BaseRepresentation
bin100011100111101000011000…
…1111100011101111011001011
31112002100011011102100100000011
41013033100301330131323023
5312031233102213242103
63030204402322252351
7122664623441023252
oct10717206174357313
91462304142310004
10313310112243403
1190915088424670
122b1817227b70b7
13105a902ac187c2
14575240c9bd799
152634dad334d6d
hex11cf431f1decb

313310112243403 has 4 divisors (see below), whose sum is σ = 341792849720088. Its totient is φ = 284827374766720.

The previous prime is 313310112243383. The next prime is 313310112243461. The reversal of 313310112243403 is 304342211013313.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-313310112243403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (313310112243463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14241368738326 + ... + 14241368738347.

It is an arithmetic number, because the mean of its divisors is an integer number (85448212430022).

Almost surely, 2313310112243403 is an apocalyptic number.

313310112243403 is a deficient number, since it is larger than the sum of its proper divisors (28482737476685).

313310112243403 is a wasteful number, since it uses less digits than its factorization.

313310112243403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28482737476684.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 313310112243403 its reverse (304342211013313), we get a palindrome (617652323256716).

The spelling of 313310112243403 in words is "three hundred thirteen trillion, three hundred ten billion, one hundred twelve million, two hundred forty-three thousand, four hundred three".

Divisors: 1 11 28482737476673 313310112243403