313321000413433 has 8 divisors (see below), whose sum is σ = 323838747894152. Its totient is φ = 302911127266176.

The previous prime is 313321000413419. The next prime is 313321000413611. The reversal of 313321000413433 is 334314000123313.

It can be written as a sum of positive squares in 4 ways, for example, as 130717993640809 + 182603006772624 = 11433197^2 + 13513068^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 313321000413433 - 2¹³ = 313321000405241 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 313321000413395 and 313321000413404.

It is not an unprimeable number, because it can be changed into a prime (313321000413133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26968577460 + ... + 26968589077.

It is an arithmetic number, because the mean of its divisors is an integer number (40479843486769).

Almost surely, 2^{313321000413433} is an apocalyptic number.

It is an amenable number.

313321000413433 is a deficient number, since it is larger than the sum of its proper divisors (10517747480719).

313321000413433 is a wasteful number, since it uses less digits than its factorization.

313321000413433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53937166731.

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 313321000413433 its reverse (334314000123313), we get a palindrome (647635000536746).

The spelling of 313321000413433 in words is "three hundred thirteen trillion, three hundred twenty-one billion, four hundred thirteen thousand, four hundred thirty-three".