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313335444113 = 1450321604871
BaseRepresentation
bin1001000111101000011…
…11110111001010010001
31002221202212220210000122
410203310033313022101
520113202333202423
6355535550000025
731431513221216
oct4436417671221
91087685823018
10313335444113
1111098076489a
12508874a6015
132371685b343
1411246269b0d
15823d2c18c8
hex48f43f7291

313335444113 has 4 divisors (see below), whose sum is σ = 313357063488. Its totient is φ = 313313824740.

The previous prime is 313335444077. The next prime is 313335444137. The reversal of 313335444113 is 311444533313.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311444533313 = 1725531804921.

It is a cyclic number.

It is not a de Polignac number, because 313335444113 - 26 = 313335444049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (313335444713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10787933 + ... + 10816938.

It is an arithmetic number, because the mean of its divisors is an integer number (78339265872).

Almost surely, 2313335444113 is an apocalyptic number.

It is an amenable number.

313335444113 is a deficient number, since it is larger than the sum of its proper divisors (21619375).

313335444113 is a wasteful number, since it uses less digits than its factorization.

313335444113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21619374.

The product of its digits is 77760, while the sum is 35.

Adding to 313335444113 its reverse (311444533313), we get a palindrome (624779977426).

The spelling of 313335444113 in words is "three hundred thirteen billion, three hundred thirty-five million, four hundred forty-four thousand, one hundred thirteen".

Divisors: 1 14503 21604871 313335444113