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31340410003 = 74477201429
BaseRepresentation
bin11101001100000010…
…001011010010010011
32222220011111210020001
4131030002023102103
51003141121110003
622221513430431
72156434042510
oct351402132223
988804453201
1031340410003
11123229319a1
1260a7a0b417
132c55cab406
141734488307
15c3664c61d
hex74c08b493

31340410003 has 4 divisors (see below), whose sum is σ = 35817611440. Its totient is φ = 26863208568.

The previous prime is 31340409967. The next prime is 31340410007. The reversal of 31340410003 is 30001404313.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30001404313 = 171764788489.

It is not a de Polignac number, because 31340410003 - 213 = 31340401811 is a prime.

It is a super-2 number, since 2×313404100032 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31340410007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2238600708 + ... + 2238600721.

It is an arithmetic number, because the mean of its divisors is an integer number (8954402860).

Almost surely, 231340410003 is an apocalyptic number.

31340410003 is a deficient number, since it is larger than the sum of its proper divisors (4477201437).

31340410003 is an equidigital number, since it uses as much as digits as its factorization.

31340410003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4477201436.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 31340410003 its reverse (30001404313), we get a palindrome (61341814316).

The spelling of 31340410003 in words is "thirty-one billion, three hundred forty million, four hundred ten thousand, three".

Divisors: 1 7 4477201429 31340410003