Base | Representation |
---|---|
bin | 101101100110110011101… |
… | …001011100010100000011 |
3 | 102002121111222212010220001 |
4 | 231212303221130110003 |
5 | 402322011024104243 |
6 | 10355432132100431 |
7 | 442266363120112 |
oct | 55466351342403 |
9 | 12077458763801 |
10 | 3134045144323 |
11 | aa9160863695 |
12 | 427495464717 |
13 | 1997017a1352 |
14 | ab98d707c79 |
15 | 567cc798a4d |
hex | 2d9b3a5c503 |
3134045144323 has 4 divisors (see below), whose sum is σ = 3134623493560. Its totient is φ = 3133466795088.
The previous prime is 3134045144281. The next prime is 3134045144339. The reversal of 3134045144323 is 3234415404313.
3134045144323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3134045144323 - 217 = 3134045013251 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3134045144123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 289166490 + ... + 289177327.
It is an arithmetic number, because the mean of its divisors is an integer number (783655873390).
Almost surely, 23134045144323 is an apocalyptic number.
3134045144323 is a deficient number, since it is larger than the sum of its proper divisors (578349237).
3134045144323 is an equidigital number, since it uses as much as digits as its factorization.
3134045144323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 578349236.
The product of its (nonzero) digits is 207360, while the sum is 37.
The spelling of 3134045144323 in words is "three trillion, one hundred thirty-four billion, forty-five million, one hundred forty-four thousand, three hundred twenty-three".
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