Base | Representation |
---|---|
bin | 1011101011001110… |
… | …1001011110111001 |
3 | 22002102100211220212 |
4 | 2322303221132321 |
5 | 22404312221213 |
6 | 1234554400505 |
7 | 140444264651 |
oct | 27263513671 |
9 | 8072324825 |
10 | 3134101433 |
11 | 1369133881 |
12 | 735730135 |
13 | 3ac407ab8 |
14 | 21a353361 |
15 | 1352329a8 |
hex | bace97b9 |
3134101433 has 4 divisors (see below), whose sum is σ = 3299054160. Its totient is φ = 2969148708.
The previous prime is 3134101409. The next prime is 3134101501. The reversal of 3134101433 is 3341014313.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3134101433 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3134101399 and 3134101408.
It is not an unprimeable number, because it can be changed into a prime (3134106433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82476335 + ... + 82476372.
It is an arithmetic number, because the mean of its divisors is an integer number (824763540).
Almost surely, 23134101433 is an apocalyptic number.
It is an amenable number.
3134101433 is a deficient number, since it is larger than the sum of its proper divisors (164952727).
3134101433 is a wasteful number, since it uses less digits than its factorization.
3134101433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 164952726.
The product of its (nonzero) digits is 1296, while the sum is 23.
The square root of 3134101433 is about 55983.0459424994. The cubic root of 3134101433 is about 1463.4268401507.
Adding to 3134101433 its reverse (3341014313), we get a palindrome (6475115746).
The spelling of 3134101433 in words is "three billion, one hundred thirty-four million, one hundred one thousand, four hundred thirty-three".
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