3134110433 has 4 divisors (see below), whose sum is σ = 3270376128. Its totient is φ = 2997844740.

The previous prime is 3134110411. The next prime is 3134110451. The reversal of 3134110433 is 3340114313.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3134110433 - 2¹² = 3134106337 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (23), and also a Moran number because the ratio is a prime number: 136265671 = 3134110433 / (3 + 1 + 3 + 4 + 1 + 1 + 0 + 4 + 3 + 3).

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 3134110399 and 3134110408.

It is not an unprimeable number, because it can be changed into a prime (3134110403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68132813 + ... + 68132858.

It is an arithmetic number, because the mean of its divisors is an integer number (817594032).

Almost surely, 2^3134110433 is an apocalyptic number.

It is an amenable number.

3134110433 is a deficient number, since it is larger than the sum of its proper divisors (136265695).

3134110433 is a wasteful number, since it uses less digits than its factorization.

3134110433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 136265694.

The product of its (nonzero) digits is 1296, while the sum is 23.

The square root of 3134110433 is about 55983.1263239201. The cubic root of 3134110433 is about 1463.4282409593.

Adding to 3134110433 its reverse (3340114313), we get a palindrome (6474224746).

The spelling of 3134110433 in words is "three billion, one hundred thirty-four million, one hundred ten thousand, four hundred thirty-three".