Base | Representation |
---|---|
bin | 100011101000100110011011… |
… | …0011011010011011100111011 |
3 | 1112002210220000200201210111022 |
4 | 1013101030312123103130323 |
5 | 312040423420321001021 |
6 | 3030345513435453055 |
7 | 123010350644246060 |
oct | 10721146633233473 |
9 | 1462726020653438 |
10 | 313443331422011 |
11 | 9096663015628a |
12 | 2b1a35015b718b |
13 | 105b876ba1543b |
14 | 5758a49826c67 |
15 | 26385a8ad41ab |
hex | 11d13366d373b |
313443331422011 has 8 divisors (see below), whose sum is σ = 358221609832704. Its totient is φ = 268665217920360.
The previous prime is 313443331421903. The next prime is 313443331422017. The reversal of 313443331422011 is 110224133344313.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-313443331422011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (313443331422017) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37127135 + ... + 44780696.
It is an arithmetic number, because the mean of its divisors is an integer number (44777701229088).
Almost surely, 2313443331422011 is an apocalyptic number.
313443331422011 is a deficient number, since it is larger than the sum of its proper divisors (44778278410693).
313443331422011 is an equidigital number, since it uses as much as digits as its factorization.
313443331422011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 82454521.
The product of its (nonzero) digits is 62208, while the sum is 35.
Adding to 313443331422011 its reverse (110224133344313), we get a palindrome (423667464766324).
The spelling of 313443331422011 in words is "three hundred thirteen trillion, four hundred forty-three billion, three hundred thirty-one million, four hundred twenty-two thousand, eleven".
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