Base | Representation |
---|---|
bin | 101101101000001101000… |
… | …000011011001010100001 |
3 | 102002202101110212020022120 |
4 | 231220031000123022201 |
5 | 402333043322404103 |
6 | 10400241005054453 |
7 | 442351466101260 |
oct | 55501500331241 |
9 | 12082343766276 |
10 | 3135544341153 |
11 | aa9860045434 |
12 | 427833557429 |
13 | 1998b0271b73 |
14 | aba9287c5d7 |
15 | 568691d5253 |
hex | 2da0d01b2a1 |
3135544341153 has 16 divisors (see below), whose sum is σ = 4778432480256. Its totient is φ = 1791567066960.
The previous prime is 3135544341151. The next prime is 3135544341187. The reversal of 3135544341153 is 3511434455313.
It is not a de Polignac number, because 3135544341153 - 21 = 3135544341151 is a prime.
It is a super-4 number, since 4×31355443411534 (a number of 51 digits) contains 4444 as substring.
It is not an unprimeable number, because it can be changed into a prime (3135544341151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6966451 + ... + 7402872.
It is an arithmetic number, because the mean of its divisors is an integer number (298652030016).
Almost surely, 23135544341153 is an apocalyptic number.
It is an amenable number.
3135544341153 is a deficient number, since it is larger than the sum of its proper divisors (1642888139103).
3135544341153 is a wasteful number, since it uses less digits than its factorization.
3135544341153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14379724.
The product of its digits is 648000, while the sum is 42.
Adding to 3135544341153 its reverse (3511434455313), we get a palindrome (6646978796466).
The spelling of 3135544341153 in words is "three trillion, one hundred thirty-five billion, five hundred forty-four million, three hundred forty-one thousand, one hundred fifty-three".
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