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3136069745041 = 6804534608797
BaseRepresentation
bin101101101000101100010…
…100101011100110010001
3102002210202002111111221211
4231220230110223212101
5402340132323320131
610400405054220121
7442400506002112
oct55505424534621
912083662444854
103136069745041
11aa9aaa683122
1242795b4b4641
1319996507cc3c
14abb02568209
155689a3ba5b1
hex2da2c52b991

3136069745041 has 4 divisors (see below), whose sum is σ = 3136075034292. Its totient is φ = 3136064455792.

The previous prime is 3136069745027. The next prime is 3136069745059. The reversal of 3136069745041 is 1405479606313.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2923091187025 + 212978558016 = 1709705^2 + 461496^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3136069745041 is a prime.

It is a super-4 number, since 4×31360697450414 (a number of 51 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3136066745041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1623946 + ... + 2984851.

It is an arithmetic number, because the mean of its divisors is an integer number (784018758573).

Almost surely, 23136069745041 is an apocalyptic number.

It is an amenable number.

3136069745041 is a deficient number, since it is larger than the sum of its proper divisors (5289251).

3136069745041 is an equidigital number, since it uses as much as digits as its factorization.

3136069745041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5289250.

The product of its (nonzero) digits is 1632960, while the sum is 49.

The spelling of 3136069745041 in words is "three trillion, one hundred thirty-six billion, sixty-nine million, seven hundred forty-five thousand, forty-one".

Divisors: 1 680453 4608797 3136069745041