31400411214113 has 4 divisors (see below), whose sum is σ = 31500732017028. Its totient is φ = 31300090411200.

The previous prime is 31400411214089. The next prime is 31400411214131. The reversal of 31400411214113 is 31141211400413.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9063369154849 + 22337042059264 = 3010543^2 + 4726208^2 .

It is a cyclic number.

It is not a de Polignac number, because 31400411214113 - 2¹⁰ = 31400411213089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31400411214173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50160400988 + ... + 50160401613.

It is an arithmetic number, because the mean of its divisors is an integer number (7875183004257).

Almost surely, 2^{31400411214113} is an apocalyptic number.

It is an amenable number.

31400411214113 is a deficient number, since it is larger than the sum of its proper divisors (100320802915).

31400411214113 is a wasteful number, since it uses less digits than its factorization.

31400411214113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100320802914.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 31400411214113 its reverse (31141211400413), we get a palindrome (62541622614526).

The spelling of 31400411214113 in words is "thirty-one trillion, four hundred billion, four hundred eleven million, two hundred fourteen thousand, one hundred thirteen".