Base | Representation |
---|---|
bin | 101101101100011110100… |
… | …010110111111111111001 |
3 | 102010012020022021022021011 |
4 | 231230132202313333321 |
5 | 402421443142131441 |
6 | 10402320223513521 |
7 | 442603302540136 |
oct | 55543642677771 |
9 | 12105208238234 |
10 | 3140133552121 |
11 | 10007a5588575 |
12 | 4286b44588a1 |
13 | 19a161c82407 |
14 | abdaa16b58d |
15 | 56a37046581 |
hex | 2db1e8b7ff9 |
3140133552121 has 4 divisors (see below), whose sum is σ = 3147127168500. Its totient is φ = 3133139935744.
The previous prime is 3140133552091. The next prime is 3140133552139. The reversal of 3140133552121 is 1212553310413.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2025284765625 + 1114848786496 = 1423125^2 + 1055864^2 .
It is a cyclic number.
It is not a de Polignac number, because 3140133552121 - 219 = 3140133027833 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3140133552421) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3496807516 + ... + 3496808413.
It is an arithmetic number, because the mean of its divisors is an integer number (786781792125).
Almost surely, 23140133552121 is an apocalyptic number.
It is an amenable number.
3140133552121 is a deficient number, since it is larger than the sum of its proper divisors (6993616379).
3140133552121 is an equidigital number, since it uses as much as digits as its factorization.
3140133552121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6993616378.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 3140133552121 its reverse (1212553310413), we get a palindrome (4352686862534).
The spelling of 3140133552121 in words is "three trillion, one hundred forty billion, one hundred thirty-three million, five hundred fifty-two thousand, one hundred twenty-one".
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