314042440301113 has 4 divisors (see below), whose sum is σ = 314043323892480. Its totient is φ = 314041556709748.

The previous prime is 314042440301039. The next prime is 314042440301123. The reversal of 314042440301113 is 311103044240413.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 314042440301113 - 2²⁵ = 314042406746681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (314042440301123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 441262345 + ... + 441973462.

It is an arithmetic number, because the mean of its divisors is an integer number (78510830973120).

Almost surely, 2^{314042440301113} is an apocalyptic number.

It is an amenable number.

314042440301113 is a deficient number, since it is larger than the sum of its proper divisors (883591367).

314042440301113 is an equidigital number, since it uses as much as digits as its factorization.

314042440301113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 883591366.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 314042440301113 its reverse (311103044240413), we get a palindrome (625145484541526).

The spelling of 314042440301113 in words is "three hundred fourteen trillion, forty-two billion, four hundred forty million, three hundred one thousand, one hundred thirteen".