Base | Representation |
---|---|
bin | 100011101101011110000000… |
… | …0000000001010000001001001 |
3 | 1112012011212002112211121112020 |
4 | 1013122330000000022001021 |
5 | 312132404230401441433 |
6 | 3032021132033435053 |
7 | 123106605626642562 |
oct | 10732740000120111 |
9 | 1465155075747466 |
10 | 314112433233993 |
11 | 910a43757369a9 |
12 | 2b29111640ba89 |
13 | 106368a19a9594 |
14 | 577d1a12b9169 |
15 | 264abba292cb3 |
hex | 11daf0000a049 |
314112433233993 has 4 divisors (see below), whose sum is σ = 418816577645328. Its totient is φ = 209408288822660.
The previous prime is 314112433233899. The next prime is 314112433234003. The reversal of 314112433233993 is 399332334211413.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 314112433233993 - 212 = 314112433229897 is a prime.
It is not an unprimeable number, because it can be changed into a prime (314112433233593) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52352072205663 + ... + 52352072205668.
It is an arithmetic number, because the mean of its divisors is an integer number (104704144411332).
Almost surely, 2314112433233993 is an apocalyptic number.
It is an amenable number.
314112433233993 is a deficient number, since it is larger than the sum of its proper divisors (104704144411335).
314112433233993 is a wasteful number, since it uses less digits than its factorization.
314112433233993 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104704144411334.
The product of its digits is 3779136, while the sum is 51.
The spelling of 314112433233993 in words is "three hundred fourteen trillion, one hundred twelve billion, four hundred thirty-three million, two hundred thirty-three thousand, nine hundred ninety-three".
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