314133102121 has 4 divisors (see below), whose sum is σ = 318821655952. Its totient is φ = 309444548292.

The previous prime is 314133102089. The next prime is 314133102161. The reversal of 314133102121 is 121201331413.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 121201331413 = 313 ⋅387224701.

It is a cyclic number.

It is not a de Polignac number, because 314133102121 - 2⁵ = 314133102089 is a prime.

It is a super-2 number, since 2×314133102121² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 314133102092 and 314133102101.

It is not an unprimeable number, because it can be changed into a prime (314133102161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2344276815 + ... + 2344276948.

It is an arithmetic number, because the mean of its divisors is an integer number (79705413988).

Almost surely, 2^314133102121 is an apocalyptic number.

It is an amenable number.

314133102121 is a deficient number, since it is larger than the sum of its proper divisors (4688553831).

314133102121 is an equidigital number, since it uses as much as digits as its factorization.

314133102121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4688553830.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 314133102121 its reverse (121201331413), we get a palindrome (435334433534).

The spelling of 314133102121 in words is "three hundred fourteen billion, one hundred thirty-three million, one hundred two thousand, one hundred twenty-one".