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31421123312035 = 519073329482759
BaseRepresentation
bin1110010010011110011001…
…11001001011100110100011
311010020211102002220222122011
413021033030321023212203
513104300430031441120
6150454355331453351
76422046504261322
oct711171471134643
9133224362828564
1031421123312035
11a014694a65316
12363575a757257
13146bccb374512
147a8b0d1280b9
153975075e2c5a
hex1c93cce4b9a3

31421123312035 has 8 divisors (see below), whose sum is σ = 37707324985440. Its totient is φ = 25135580642304.

The previous prime is 31421123311999. The next prime is 31421123312057. The reversal of 31421123312035 is 53021332112413.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 31421123312035 - 217 = 31421123180963 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31421123311988 and 31421123312006.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 164646015 + ... + 164836744.

It is an arithmetic number, because the mean of its divisors is an integer number (4713415623180).

Almost surely, 231421123312035 is an apocalyptic number.

31421123312035 is a deficient number, since it is larger than the sum of its proper divisors (6286201673405).

31421123312035 is a wasteful number, since it uses less digits than its factorization.

31421123312035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 329501837.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 31421123312035 its reverse (53021332112413), we get a palindrome (84442455424448).

The spelling of 31421123312035 in words is "thirty-one trillion, four hundred twenty-one billion, one hundred twenty-three million, three hundred twelve thousand, thirty-five".

Divisors: 1 5 19073 95365 329482759 1647413795 6284224662407 31421123312035