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31421400403 = 47737658219
BaseRepresentation
bin11101010000110111…
…001000010101010011
310000002210220112011111
4131100313020111103
51003322334303103
622233525354151
72161436332231
oct352067102523
9100083815144
1031421400403
111236461a208
12610ab68957
132c699c7523
14174112b951
15c3d7e986d
hex750dc8553

31421400403 has 4 divisors (see below), whose sum is σ = 31422106360. Its totient is φ = 31420694448.

The previous prime is 31421400401. The next prime is 31421400457. The reversal of 31421400403 is 30400412413.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 31421400403 - 21 = 31421400401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31421400401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 281373 + ... + 376846.

It is an arithmetic number, because the mean of its divisors is an integer number (7855526590).

Almost surely, 231421400403 is an apocalyptic number.

31421400403 is a deficient number, since it is larger than the sum of its proper divisors (705957).

31421400403 is an equidigital number, since it uses as much as digits as its factorization.

31421400403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 705956.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 31421400403 its reverse (30400412413), we get a palindrome (61821812816).

The spelling of 31421400403 in words is "thirty-one billion, four hundred twenty-one million, four hundred thousand, four hundred three".

Divisors: 1 47737 658219 31421400403