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31425142555 = 56285028511
BaseRepresentation
bin11101010001000101…
…011001111100011011
310000010001221122102201
4131101011121330123
51003324314030210
622234141511031
72161513206262
oct352105317433
9100101848381
1031425142555
11123667457a4
126110272477
132c6a707911
1417418235d9
15c3dcd853a
hex751159f1b

31425142555 has 4 divisors (see below), whose sum is σ = 37710171072. Its totient is φ = 25140114040.

The previous prime is 31425142523. The next prime is 31425142561. The reversal of 31425142555 is 55524152413.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 55524152413 = 181306763273.

It is not a de Polignac number, because 31425142555 - 25 = 31425142523 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3142514251 + ... + 3142514260.

It is an arithmetic number, because the mean of its divisors is an integer number (9427542768).

Almost surely, 231425142555 is an apocalyptic number.

31425142555 is a deficient number, since it is larger than the sum of its proper divisors (6285028517).

31425142555 is an equidigital number, since it uses as much as digits as its factorization.

31425142555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6285028516.

The product of its digits is 120000, while the sum is 37.

Adding to 31425142555 its reverse (55524152413), we get a palindrome (86949294968).

The spelling of 31425142555 in words is "thirty-one billion, four hundred twenty-five million, one hundred forty-two thousand, five hundred fifty-five".

Divisors: 1 5 6285028511 31425142555