Base | Representation |
---|---|
bin | 101101101111010000000… |
… | …101100100001110011011 |
3 | 102010110220220010222101101 |
4 | 231233100011210032123 |
5 | 402444043211312103 |
6 | 10403531550532231 |
7 | 443040151666621 |
oct | 55572005441633 |
9 | 12113826128341 |
10 | 3143112213403 |
11 | 1001a939a3908 |
12 | 4291a5b07077 |
13 | 19a518105096 |
14 | ac1ad9bb511 |
15 | 56b5d7c2a1d |
hex | 2dbd016439b |
3143112213403 has 4 divisors (see below), whose sum is σ = 3170927365848. Its totient is φ = 3115297060960.
The previous prime is 3143112213349. The next prime is 3143112213413. The reversal of 3143112213403 is 3043122113413.
3143112213403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3143112213403 - 225 = 3143078658971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3143112213413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13907576053 + ... + 13907576278.
It is an arithmetic number, because the mean of its divisors is an integer number (792731841462).
Almost surely, 23143112213403 is an apocalyptic number.
3143112213403 is a deficient number, since it is larger than the sum of its proper divisors (27815152445).
3143112213403 is a wasteful number, since it uses less digits than its factorization.
3143112213403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27815152444.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 3143112213403 its reverse (3043122113413), we get a palindrome (6186234326816).
The spelling of 3143112213403 in words is "three trillion, one hundred forty-three billion, one hundred twelve million, two hundred thirteen thousand, four hundred three".
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