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3143112213403 = 11327815152331
BaseRepresentation
bin101101101111010000000…
…101100100001110011011
3102010110220220010222101101
4231233100011210032123
5402444043211312103
610403531550532231
7443040151666621
oct55572005441633
912113826128341
103143112213403
111001a939a3908
124291a5b07077
1319a518105096
14ac1ad9bb511
1556b5d7c2a1d
hex2dbd016439b

3143112213403 has 4 divisors (see below), whose sum is σ = 3170927365848. Its totient is φ = 3115297060960.

The previous prime is 3143112213349. The next prime is 3143112213413. The reversal of 3143112213403 is 3043122113413.

3143112213403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3143112213403 - 225 = 3143078658971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3143112213413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13907576053 + ... + 13907576278.

It is an arithmetic number, because the mean of its divisors is an integer number (792731841462).

Almost surely, 23143112213403 is an apocalyptic number.

3143112213403 is a deficient number, since it is larger than the sum of its proper divisors (27815152445).

3143112213403 is a wasteful number, since it uses less digits than its factorization.

3143112213403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27815152444.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 3143112213403 its reverse (3043122113413), we get a palindrome (6186234326816).

The spelling of 3143112213403 in words is "three trillion, one hundred forty-three billion, one hundred twelve million, two hundred thirteen thousand, four hundred three".

Divisors: 1 113 27815152331 3143112213403