Base | Representation |
---|---|
bin | 11101010010100100… |
… | …101100000011110001 |
3 | 10000011210221122122022 |
4 | 131102210230003301 |
5 | 1003402212323213 |
6 | 22240433121225 |
7 | 2162235420134 |
oct | 352244540361 |
9 | 100153848568 |
10 | 31450120433 |
11 | 12379855a76 |
12 | 61186b9215 |
13 | 2c72941a24 |
14 | 1744c8621b |
15 | c410be308 |
hex | 75292c0f1 |
31450120433 has 4 divisors (see below), whose sum is σ = 31468988400. Its totient is φ = 31431252468.
The previous prime is 31450120409. The next prime is 31450120439. The reversal of 31450120433 is 33402105413.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 31450120433 - 222 = 31445926129 is a prime.
It is a super-2 number, since 2×314501204332 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31450120439) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9431483 + ... + 9434816.
It is an arithmetic number, because the mean of its divisors is an integer number (7867247100).
Almost surely, 231450120433 is an apocalyptic number.
It is an amenable number.
31450120433 is a deficient number, since it is larger than the sum of its proper divisors (18867967).
31450120433 is a wasteful number, since it uses less digits than its factorization.
31450120433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18867966.
The product of its (nonzero) digits is 4320, while the sum is 26.
Adding to 31450120433 its reverse (33402105413), we get a palindrome (64852225846).
The spelling of 31450120433 in words is "thirty-one billion, four hundred fifty million, one hundred twenty thousand, four hundred thirty-three".
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