3145103473 has 4 divisors (see below), whose sum is σ = 3166211700. Its totient is φ = 3123995248.

The previous prime is 3145103471. The next prime is 3145103477. The reversal of 3145103473 is 3743015413.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 405941904 + 2739161569 = 20148^2 + 52337^2 .

It is a cyclic number.

It is not a de Polignac number, because 3145103473 - 2¹ = 3145103471 is a prime.

It is a super-3 number, since 3×3145103473³ (a number of 29 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3145103471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10553890 + ... + 10554187.

It is an arithmetic number, because the mean of its divisors is an integer number (791552925).

Almost surely, 2^3145103473 is an apocalyptic number.

It is an amenable number.

3145103473 is a deficient number, since it is larger than the sum of its proper divisors (21108227).

3145103473 is a wasteful number, since it uses less digits than its factorization.

3145103473 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21108226.

The product of its (nonzero) digits is 15120, while the sum is 31.

The square root of 3145103473 is about 56081.2221068692. Note that the first 3 decimals coincide. The cubic root of 3145103473 is about 1465.1372588608.

Adding to 3145103473 its reverse (3743015413), we get a palindrome (6888118886).

The spelling of 3145103473 in words is "three billion, one hundred forty-five million, one hundred three thousand, four hundred seventy-three".