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314523140035 = 5134838817539
BaseRepresentation
bin1001001001110110000…
…10100011111111000011
31010001211122202222112111
410210323002203333003
520123120410440120
6400253454240151
731503114402436
oct4447302437703
91101748688474
10314523140035
11111430127375
1250b591b6057
13238759352b0
1411319cb581d
1582ac6cb75a
hex493b0a3fc3

314523140035 has 8 divisors (see below), whose sum is σ = 406460673360. Its totient is φ = 232263241824.

The previous prime is 314523139999. The next prime is 314523140053. The reversal of 314523140035 is 530041325413.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 314523140035 - 219 = 314522615747 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 314523139979 and 314523140006.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2419408705 + ... + 2419408834.

It is an arithmetic number, because the mean of its divisors is an integer number (50807584170).

Almost surely, 2314523140035 is an apocalyptic number.

314523140035 is a deficient number, since it is larger than the sum of its proper divisors (91937533325).

314523140035 is a wasteful number, since it uses less digits than its factorization.

314523140035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4838817557.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 314523140035 its reverse (530041325413), we get a palindrome (844564465448).

The spelling of 314523140035 in words is "three hundred fourteen billion, five hundred twenty-three million, one hundred forty thousand, thirty-five".

Divisors: 1 5 13 65 4838817539 24194087695 62904628007 314523140035