31458050113 has 4 divisors (see below), whose sum is σ = 35952057280. Its totient is φ = 26964042948.

The previous prime is 31458050111. The next prime is 31458050161. The reversal of 31458050113 is 31105085413.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31105085413 = 61 ⋅509919433.

It is a cyclic number.

It is not a de Polignac number, because 31458050113 - 2¹ = 31458050111 is a prime.

It is a super-3 number, since 3×31458050113³ (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31458050111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2247003573 + ... + 2247003586.

It is an arithmetic number, because the mean of its divisors is an integer number (8988014320).

Almost surely, 2^31458050113 is an apocalyptic number.

It is an amenable number.

31458050113 is a deficient number, since it is larger than the sum of its proper divisors (4494007167).

31458050113 is an equidigital number, since it uses as much as digits as its factorization.

31458050113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4494007166.

The product of its (nonzero) digits is 7200, while the sum is 31.

The spelling of 31458050113 in words is "thirty-one billion, four hundred fifty-eight million, fifty thousand, one hundred thirteen".