31504403141131 has 4 divisors (see below), whose sum is σ = 31504422513952. Its totient is φ = 31504383768312.

The previous prime is 31504403141093. The next prime is 31504403141173. The reversal of 31504403141131 is 13114130440513.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 31504403141131 - 2¹⁵ = 31504403108363 is a prime.

It is a super-2 number, since 2×31504403141131² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31504403141093 and 31504403141102.

It is not an unprimeable number, because it can be changed into a prime (31504403141231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6998451 + ... + 10582396.

It is an arithmetic number, because the mean of its divisors is an integer number (7876105628488).

Almost surely, 2^{31504403141131} is an apocalyptic number.

31504403141131 is a deficient number, since it is larger than the sum of its proper divisors (19372821).

31504403141131 is a wasteful number, since it uses less digits than its factorization.

31504403141131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19372820.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 31504403141131 its reverse (13114130440513), we get a palindrome (44618533581644).

The spelling of 31504403141131 in words is "thirty-one trillion, five hundred four billion, four hundred three million, one hundred forty-one thousand, one hundred thirty-one".