Base | Representation |
---|---|
bin | 11101010101110011… |
… | …110111001110111011 |
3 | 10000022121010212101011 |
4 | 131111303313032323 |
5 | 1004010113230021 |
6 | 22250053134351 |
7 | 2163465144115 |
oct | 352563671673 |
9 | 100277125334 |
10 | 31504430011 |
11 | 123a747a61a |
12 | 613292a3b7 |
13 | 2c80c78882 |
14 | 174c1823b5 |
15 | c45c4ade1 |
hex | 755cf73bb |
31504430011 has 4 divisors (see below), whose sum is σ = 31524536512. Its totient is φ = 31484323512.
The previous prime is 31504429993. The next prime is 31504430017. The reversal of 31504430011 is 11003440513.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31504430011 - 211 = 31504427963 is a prime.
It is a super-2 number, since 2×315044300112 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31504430017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10050900 + ... + 10054033.
It is an arithmetic number, because the mean of its divisors is an integer number (7881134128).
Almost surely, 231504430011 is an apocalyptic number.
31504430011 is a deficient number, since it is larger than the sum of its proper divisors (20106501).
31504430011 is a wasteful number, since it uses less digits than its factorization.
31504430011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20106500.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 31504430011 its reverse (11003440513), we get a palindrome (42507870524).
The spelling of 31504430011 in words is "thirty-one billion, five hundred four million, four hundred thirty thousand, eleven".
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