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315104500153 = 518960725477
BaseRepresentation
bin1001001010111011011…
…00010001100110111001
31010010100011201010200201
410211131230101212321
520130313223001103
6400431303002201
731523404026052
oct4453554214671
91103304633621
10315104500153
111116a9303883
125109ba39361
1323939205871
14113731a9729
1582e376651d
hex495db119b9

315104500153 has 4 divisors (see below), whose sum is σ = 315165230820. Its totient is φ = 315043769488.

The previous prime is 315104500141. The next prime is 315104500159. The reversal of 315104500153 is 351005401513.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 274714353424 + 40390146729 = 524132^2 + 200973^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-315104500153 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (315104500159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30357550 + ... + 30367927.

It is an arithmetic number, because the mean of its divisors is an integer number (78791307705).

Almost surely, 2315104500153 is an apocalyptic number.

It is an amenable number.

315104500153 is a deficient number, since it is larger than the sum of its proper divisors (60730667).

315104500153 is an equidigital number, since it uses as much as digits as its factorization.

315104500153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60730666.

The product of its (nonzero) digits is 4500, while the sum is 28.

Adding to 315104500153 its reverse (351005401513), we get a palindrome (666109901666).

The spelling of 315104500153 in words is "three hundred fifteen billion, one hundred four million, five hundred thousand, one hundred fifty-three".

Divisors: 1 5189 60725477 315104500153