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315114344043 = 3105038114681
BaseRepresentation
bin1001001010111100100…
…01110100111001101011
31010010100212020020222020
410211132101310321223
520130323233002133
6400432253555523
731523553505332
oct4453621647153
91103325206866
10315114344043
11111703917724
12510a31a5ba3
132393b271355
141137460cd19
1582e455d0b3
hex495e474e6b

315114344043 has 4 divisors (see below), whose sum is σ = 420152458728. Its totient is φ = 210076229360.

The previous prime is 315114343993. The next prime is 315114344053. The reversal of 315114344043 is 340443411513.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 315114344043 - 214 = 315114327659 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 315114343995 and 315114344013.

It is not an unprimeable number, because it can be changed into a prime (315114344053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52519057338 + ... + 52519057343.

It is an arithmetic number, because the mean of its divisors is an integer number (105038114682).

Almost surely, 2315114344043 is an apocalyptic number.

315114344043 is a deficient number, since it is larger than the sum of its proper divisors (105038114685).

315114344043 is a wasteful number, since it uses less digits than its factorization.

315114344043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105038114684.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 315114344043 its reverse (340443411513), we get a palindrome (655557755556).

The spelling of 315114344043 in words is "three hundred fifteen billion, one hundred fourteen million, three hundred forty-four thousand, forty-three".

Divisors: 1 3 105038114681 315114344043