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315250314241 = 7110934062347
BaseRepresentation
bin1001001011001100110…
…00100000110000000001
31010010201100002021000111
410211212120200300001
520131113040023431
6400453552151321
731530124313032
oct4454630406001
91103640067014
10315250314241
11111773647095
1251120838541
132396049a3a5
14113886c4a89
15830146a7b1
hex4966620c01

315250314241 has 8 divisors (see below), whose sum is σ = 319983027264. Its totient is φ = 310525728240.

The previous prime is 315250314191. The next prime is 315250314263. The reversal of 315250314241 is 142413052513.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 315250314241 - 215 = 315250281473 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (315250314271) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1953571 + ... + 2108776.

It is an arithmetic number, because the mean of its divisors is an integer number (39997878408).

Almost surely, 2315250314241 is an apocalyptic number.

It is an amenable number.

315250314241 is a deficient number, since it is larger than the sum of its proper divisors (4732713023).

315250314241 is a wasteful number, since it uses less digits than its factorization.

315250314241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4063511.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 315250314241 its reverse (142413052513), we get a palindrome (457663366754).

The spelling of 315250314241 in words is "three hundred fifteen billion, two hundred fifty million, three hundred fourteen thousand, two hundred forty-one".

Divisors: 1 71 1093 77603 4062347 288426637 4440145271 315250314241