Base | Representation |
---|---|
bin | 101101111000000010000… |
… | …111000100111101111011 |
3 | 102011101021000211112122200 |
4 | 231320002013010331323 |
5 | 403122401044430201 |
6 | 10412131343121243 |
7 | 443522625543363 |
oct | 55700207047573 |
9 | 12141230745580 |
10 | 3152541405051 |
11 | 1005a92489085 |
12 | 42ab978a3223 |
13 | 19b38b777a1c |
14 | ac825dd59a3 |
15 | 570114cc386 |
hex | 2de021c4f7b |
3152541405051 has 6 divisors (see below), whose sum is σ = 4553670918420. Its totient is φ = 2101694270028.
The previous prime is 3152541405011. The next prime is 3152541405119. The reversal of 3152541405051 is 1505041452513.
3152541405051 is a `hidden beast` number, since 3 + 1 + 5 + 2 + 5 + 4 + 140 + 505 + 1 = 666.
It is not a de Polignac number, because 3152541405051 - 221 = 3152539307899 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3152541404997 and 3152541405015.
It is not an unprimeable number, because it can be changed into a prime (3152541405011) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 175141189161 + ... + 175141189178.
It is an arithmetic number, because the mean of its divisors is an integer number (758945153070).
Almost surely, 23152541405051 is an apocalyptic number.
3152541405051 is a deficient number, since it is larger than the sum of its proper divisors (1401129513369).
3152541405051 is a wasteful number, since it uses less digits than its factorization.
3152541405051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 350282378345 (or 350282378342 counting only the distinct ones).
The product of its (nonzero) digits is 60000, while the sum is 36.
Adding to 3152541405051 its reverse (1505041452513), we get a palindrome (4657582857564).
The spelling of 3152541405051 in words is "three trillion, one hundred fifty-two billion, five hundred forty-one million, four hundred five thousand, fifty-one".
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