3153050450113 has 4 divisors (see below), whose sum is σ = 3338524006020. Its totient is φ = 2967576894208.

The previous prime is 3153050450063. The next prime is 3153050450117. The reversal of 3153050450113 is 3110540503513.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 922950254209 + 2230100195904 = 960703^2 + 1493352^2 .

It is a cyclic number.

It is not a de Polignac number, because 3153050450113 - 2³⁷ = 3015611496641 is a prime.

It is not an unprimeable number, because it can be changed into a prime (3153050450117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92736777928 + ... + 92736777961.

It is an arithmetic number, because the mean of its divisors is an integer number (834631001505).

Almost surely, 2^{3153050450113} is an apocalyptic number.

It is an amenable number.

3153050450113 is a deficient number, since it is larger than the sum of its proper divisors (185473555907).

3153050450113 is a wasteful number, since it uses less digits than its factorization.

3153050450113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 185473555906.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 3153050450113 its reverse (3110540503513), we get a palindrome (6263590953626).

The spelling of 3153050450113 in words is "three trillion, one hundred fifty-three billion, fifty million, four hundred fifty thousand, one hundred thirteen".