Base | Representation |
---|---|
bin | 100011110110001001100010… |
… | …1111101010101101100011011 |
3 | 1112100101220111122210020210111 |
4 | 1013230103011331111230123 |
5 | 312311431040320401042 |
6 | 3034333155004425151 |
7 | 123262032145621405 |
oct | 10754230575255433 |
9 | 1470356448706714 |
10 | 315305460325147 |
11 | 915143273a2406 |
12 | 2b4443888481b7 |
13 | 106c223c785306 |
14 | 57c0c196d9b75 |
15 | 266bc42c16517 |
hex | 11ec4c5f55b1b |
315305460325147 has 4 divisors (see below), whose sum is σ = 315550072785960. Its totient is φ = 315060847864336.
The previous prime is 315305460325067. The next prime is 315305460325153. The reversal of 315305460325147 is 741523064503513.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 315305460325147 - 27 = 315305460325019 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 315305460325147.
It is not an unprimeable number, because it can be changed into a prime (315305460325187) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 122306228473 + ... + 122306231050.
It is an arithmetic number, because the mean of its divisors is an integer number (78887518196490).
Almost surely, 2315305460325147 is an apocalyptic number.
315305460325147 is a deficient number, since it is larger than the sum of its proper divisors (244612460813).
315305460325147 is a wasteful number, since it uses less digits than its factorization.
315305460325147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 244612460812.
The product of its (nonzero) digits is 4536000, while the sum is 49.
The spelling of 315305460325147 in words is "three hundred fifteen trillion, three hundred five billion, four hundred sixty million, three hundred twenty-five thousand, one hundred forty-seven".
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