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315334055521 = 2313710176327
BaseRepresentation
bin1001001011010110101…
…11111101011001100001
31010010221011122202110101
410211223113331121201
520131301004234041
6400510143102401
731532162150512
oct4455327753141
91103834582411
10315334055521
11111806943161
12511448a1a01
132397493a644
1411395882a09
1583089acb31
hex496b5fd661

315334055521 has 4 divisors (see below), whose sum is σ = 329044231872. Its totient is φ = 301623879172.

The previous prime is 315334055483. The next prime is 315334055527. The reversal of 315334055521 is 125550433513.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 125550433513 = 683183822011.

It is a cyclic number.

It is not a de Polignac number, because 315334055521 - 221 = 315331958369 is a prime.

It is a super-2 number, since 2×3153340555212 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (315334055527) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6855088141 + ... + 6855088186.

It is an arithmetic number, because the mean of its divisors is an integer number (82261057968).

Almost surely, 2315334055521 is an apocalyptic number.

It is an amenable number.

315334055521 is a deficient number, since it is larger than the sum of its proper divisors (13710176351).

315334055521 is a wasteful number, since it uses less digits than its factorization.

315334055521 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13710176350.

The product of its (nonzero) digits is 135000, while the sum is 37.

The spelling of 315334055521 in words is "three hundred fifteen billion, three hundred thirty-four million, fifty-five thousand, five hundred twenty-one".

Divisors: 1 23 13710176327 315334055521