Base | Representation |
---|---|
bin | 100011110110111111001110… |
… | …0010010101101011101111001 |
3 | 1112100210221000200100211002011 |
4 | 1013231332130102231131321 |
5 | 312320323121200321330 |
6 | 3034502140355205521 |
7 | 123303252421612525 |
oct | 10755763422553571 |
9 | 1470727020324064 |
10 | 315420725401465 |
11 | 915591a6540262 |
12 | 2b4627968a68a1 |
13 | 1070007ba01798 |
14 | 57c6631c62d85 |
15 | 266ec3c17682a |
hex | 11edf9c4ad779 |
315420725401465 has 4 divisors (see below), whose sum is σ = 378504870481764. Its totient is φ = 252336580321168.
The previous prime is 315420725401319. The next prime is 315420725401471. The reversal of 315420725401465 is 564104527024513.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 198382492468224 + 117038232933241 = 14084832^2 + 10818421^2 .
It is a cyclic number.
It is not a de Polignac number, because 315420725401465 - 217 = 315420725270393 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31542072540142 + ... + 31542072540151.
It is an arithmetic number, because the mean of its divisors is an integer number (94626217620441).
Almost surely, 2315420725401465 is an apocalyptic number.
It is an amenable number.
315420725401465 is a deficient number, since it is larger than the sum of its proper divisors (63084145080299).
315420725401465 is an equidigital number, since it uses as much as digits as its factorization.
315420725401465 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63084145080298.
The product of its (nonzero) digits is 4032000, while the sum is 49.
The spelling of 315420725401465 in words is "three hundred fifteen trillion, four hundred twenty billion, seven hundred twenty-five million, four hundred one thousand, four hundred sixty-five".
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