31555043401441 has 4 divisors (see below), whose sum is σ = 36062906744512. Its totient is φ = 27047180058372.

The previous prime is 31555043401403. The next prime is 31555043401447. The reversal of 31555043401441 is 14410434055513.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31555043401441 - 2¹¹ = 31555043399393 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31555043401394 and 31555043401403.

It is not an unprimeable number, because it can be changed into a prime (31555043401447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2253931671525 + ... + 2253931671538.

It is an arithmetic number, because the mean of its divisors is an integer number (9015726686128).

Almost surely, 2^{31555043401441} is an apocalyptic number.

It is an amenable number.

31555043401441 is a deficient number, since it is larger than the sum of its proper divisors (4507863343071).

31555043401441 is an equidigital number, since it uses as much as digits as its factorization.

31555043401441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4507863343070.

The product of its (nonzero) digits is 288000, while the sum is 40.

Adding to 31555043401441 its reverse (14410434055513), we get a palindrome (45965477456954).

The spelling of 31555043401441 in words is "thirty-one trillion, five hundred fifty-five billion, forty-three million, four hundred one thousand, four hundred forty-one".