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316214315257 = 3111016766287
BaseRepresentation
bin1001001100111111101…
…01111000100011111001
31010020012112000120210211
410212133311320203321
520140101331042012
6401133350111121
731563041221441
oct4463765704371
91106175016724
10316214315257
11112118812345
125134b64b4a1
1323a85111ba9
141143a741121
15835adda6a7
hex499fd788f9

316214315257 has 4 divisors (see below), whose sum is σ = 317231081856. Its totient is φ = 315197548660.

The previous prime is 316214315251. The next prime is 316214315279. The reversal of 316214315257 is 752513412613.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 316214315257 - 211 = 316214313209 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (316214315251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 508382833 + ... + 508383454.

It is an arithmetic number, because the mean of its divisors is an integer number (79307770464).

Almost surely, 2316214315257 is an apocalyptic number.

It is an amenable number.

316214315257 is a deficient number, since it is larger than the sum of its proper divisors (1016766599).

316214315257 is a wasteful number, since it uses less digits than its factorization.

316214315257 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1016766598.

The product of its digits is 151200, while the sum is 40.

The spelling of 316214315257 in words is "three hundred sixteen billion, two hundred fourteen million, three hundred fifteen thousand, two hundred fifty-seven".

Divisors: 1 311 1016766287 316214315257