3164013201 has 4 divisors (see below), whose sum is σ = 4218684272. Its totient is φ = 2109342132.

The previous prime is 3164013199. The next prime is 3164013277. The reversal of 3164013201 is 1023104613.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1023104613 = 3 ⋅341034871.

It is not a de Polignac number, because 3164013201 - 2¹ = 3164013199 is a prime.

It is a super-2 number, since 2×3164013201² = 20021959072204532802, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3164003201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 527335531 + ... + 527335536.

It is an arithmetic number, because the mean of its divisors is an integer number (1054671068).

Almost surely, 2^3164013201 is an apocalyptic number.

It is an amenable number.

3164013201 is a deficient number, since it is larger than the sum of its proper divisors (1054671071).

3164013201 is a wasteful number, since it uses less digits than its factorization.

3164013201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1054671070.

The product of its (nonzero) digits is 432, while the sum is 21.

The square root of 3164013201 is about 56249.5617849597. The cubic root of 3164013201 is about 1468.0677407445.

Adding to 3164013201 its reverse (1023104613), we get a palindrome (4187117814).

The spelling of 3164013201 in words is "three billion, one hundred sixty-four million, thirteen thousand, two hundred one".