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31944477121 = 73437595577
BaseRepresentation
bin11101110000000010…
…100000100111000001
310001110021011120112021
4131300002200213001
51010410241231441
622401453001441
72210420401234
oct356002404701
9101407146467
1031944477121
1112602908517
126236183281
13302119c28b
1417907ad41b
15c6e6c03d1
hex7700a09c1

31944477121 has 4 divisors (see below), whose sum is σ = 32382072772. Its totient is φ = 31506881472.

The previous prime is 31944477119. The next prime is 31944477127. The reversal of 31944477121 is 12177444913.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 20615216400 + 11329260721 = 143580^2 + 106439^2 .

It is a cyclic number.

It is not a de Polignac number, because 31944477121 - 21 = 31944477119 is a prime.

It is a super-3 number, since 3×319444771213 (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31944477127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218797716 + ... + 218797861.

It is an arithmetic number, because the mean of its divisors is an integer number (8095518193).

Almost surely, 231944477121 is an apocalyptic number.

It is an amenable number.

31944477121 is a deficient number, since it is larger than the sum of its proper divisors (437595651).

31944477121 is an equidigital number, since it uses as much as digits as its factorization.

31944477121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437595650.

The product of its digits is 169344, while the sum is 43.

The spelling of 31944477121 in words is "thirty-one billion, nine hundred forty-four million, four hundred seventy-seven thousand, one hundred twenty-one".

Divisors: 1 73 437595577 31944477121