Base | Representation |
---|---|
bin | 11101110000100000… |
… | …110101110001110011 |
3 | 10001110211010112021201 |
4 | 131300200311301303 |
5 | 1010414310200042 |
6 | 22402335232031 |
7 | 2210545105123 |
oct | 356040656163 |
9 | 101424115251 |
10 | 31952428147 |
11 | 12607349212 |
12 | 6238978617 |
13 | 3022a24323 |
14 | 179187cc83 |
15 | c702411b7 |
hex | 770835c73 |
31952428147 has 4 divisors (see below), whose sum is σ = 32262646000. Its totient is φ = 31642210296.
The previous prime is 31952428133. The next prime is 31952428213. The reversal of 31952428147 is 74182425913.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 74182425913 = 293 ⋅253182341.
It is a cyclic number.
It is not a de Polignac number, because 31952428147 - 27 = 31952428019 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 31952428097 and 31952428106.
It is not an unprimeable number, because it can be changed into a prime (31952428447) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 155108772 + ... + 155108977.
It is an arithmetic number, because the mean of its divisors is an integer number (8065661500).
Almost surely, 231952428147 is an apocalyptic number.
31952428147 is a deficient number, since it is larger than the sum of its proper divisors (310217853).
31952428147 is a wasteful number, since it uses less digits than its factorization.
31952428147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 310217852.
The product of its digits is 483840, while the sum is 46.
It can be divided in two parts, 3195 and 2428147, that added together give a palindrome (2431342).
The spelling of 31952428147 in words is "thirty-one billion, nine hundred fifty-two million, four hundred twenty-eight thousand, one hundred forty-seven".
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