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320031140241 = 3106677046747
BaseRepresentation
bin1001010100000110101…
…01111010100110010001
31010121001112001101101010
410222003111322212101
520220410432441431
6403004214001133
732056445544201
oct4520325724621
91117045041333
10320031140241
111137a726545a
12520359461a9
1324242aba507
14116bd612401
1584d102b846
hex4a8357a991

320031140241 has 4 divisors (see below), whose sum is σ = 426708186992. Its totient is φ = 213354093492.

The previous prime is 320031140227. The next prime is 320031140287. The reversal of 320031140241 is 142041130023.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 320031140241 - 213 = 320031132049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (320031140641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53338523371 + ... + 53338523376.

It is an arithmetic number, because the mean of its divisors is an integer number (106677046748).

Almost surely, 2320031140241 is an apocalyptic number.

It is an amenable number.

320031140241 is a deficient number, since it is larger than the sum of its proper divisors (106677046751).

320031140241 is a wasteful number, since it uses less digits than its factorization.

320031140241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106677046750.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 320031140241 its reverse (142041130023), we get a palindrome (462072270264).

The spelling of 320031140241 in words is "three hundred twenty billion, thirty-one million, one hundred forty thousand, two hundred forty-one".

Divisors: 1 3 106677046747 320031140241