3200433134113 has 4 divisors (see below), whose sum is σ = 3200467823280. Its totient is φ = 3200398444948.

The previous prime is 3200433134099. The next prime is 3200433134131. The reversal of 3200433134113 is 3114313340023.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3200433134113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3200433134413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17205823 + ... + 17390836.

It is an arithmetic number, because the mean of its divisors is an integer number (800116955820).

Almost surely, 2^{3200433134113} is an apocalyptic number.

It is an amenable number.

3200433134113 is a deficient number, since it is larger than the sum of its proper divisors (34689167).

3200433134113 is an equidigital number, since it uses as much as digits as its factorization.

3200433134113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34689166.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 3200433134113 its reverse (3114313340023), we get a palindrome (6314746474136).

The spelling of 3200433134113 in words is "three trillion, two hundred billion, four hundred thirty-three million, one hundred thirty-four thousand, one hundred thirteen".