Base | Representation |
---|---|
bin | 11101110011100111… |
… | …000110111110110001 |
3 | 10001121102221010112202 |
4 | 131303213012332301 |
5 | 1011021111344441 |
6 | 22411433232545 |
7 | 2212045636505 |
oct | 356347067661 |
9 | 101542833482 |
10 | 32004403121 |
11 | 12633718839 |
12 | 6252262755 |
13 | 3030721652 |
14 | 179872c305 |
15 | c74aab19b |
hex | 7739c6fb1 |
32004403121 has 4 divisors (see below), whose sum is σ = 32015972352. Its totient is φ = 31992833892.
The previous prime is 32004403117. The next prime is 32004403127. The reversal of 32004403121 is 12130440023.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 32004403121 - 22 = 32004403117 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 32004403093 and 32004403102.
It is not an unprimeable number, because it can be changed into a prime (32004403127) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5780465 + ... + 5785998.
It is an arithmetic number, because the mean of its divisors is an integer number (8003993088).
Almost surely, 232004403121 is an apocalyptic number.
It is an amenable number.
32004403121 is a deficient number, since it is larger than the sum of its proper divisors (11569231).
32004403121 is a wasteful number, since it uses less digits than its factorization.
32004403121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11569230.
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 32004403121 its reverse (12130440023), we get a palindrome (44134843144).
The spelling of 32004403121 in words is "thirty-two billion, four million, four hundred three thousand, one hundred twenty-one".
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