Base | Representation |
---|---|
bin | 101110100101001100111… |
… | …010110010010001100011 |
3 | 102100000110001121001011010 |
4 | 232211030322302101203 |
5 | 404421213011123321 |
6 | 10450312112152003 |
7 | 450160532350353 |
oct | 56451472622143 |
9 | 12300401531133 |
10 | 3201041114211 |
11 | 1024610292446 |
12 | 438472238603 |
13 | 1a2b1a752c95 |
14 | b0d07388b63 |
15 | 583ee2bb676 |
hex | 2e94ceb2463 |
3201041114211 has 16 divisors (see below), whose sum is σ = 4405973419008. Its totient is φ = 2065075591200.
The previous prime is 3201041114189. The next prime is 3201041114231. The reversal of 3201041114211 is 1124111401023.
3201041114211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3201041114211 - 215 = 3201041081443 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3201041114231) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 802681 + ... + 2654501.
It is an arithmetic number, because the mean of its divisors is an integer number (275373338688).
Almost surely, 23201041114211 is an apocalyptic number.
3201041114211 is a gapful number since it is divisible by the number (31) formed by its first and last digit.
3201041114211 is a deficient number, since it is larger than the sum of its proper divisors (1204932304797).
3201041114211 is a wasteful number, since it uses less digits than its factorization.
3201041114211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1870442.
The product of its (nonzero) digits is 192, while the sum is 21.
Adding to 3201041114211 its reverse (1124111401023), we get a palindrome (4325152515234).
The spelling of 3201041114211 in words is "three trillion, two hundred one billion, forty-one million, one hundred fourteen thousand, two hundred eleven".
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