Base | Representation |
---|---|
bin | 11101110100001000… |
… | …000001011111110011 |
3 | 10001122001011111100001 |
4 | 131310020001133303 |
5 | 1011030314001121 |
6 | 22412342210431 |
7 | 2212212164044 |
oct | 356410013763 |
9 | 101561144301 |
10 | 32013031411 |
11 | 12638581359 |
12 | 6255123a17 |
13 | 3032452a4a |
14 | 17999368cb |
15 | c75712991 |
hex | 7742017f3 |
32013031411 has 4 divisors (see below), whose sum is σ = 32013445824. Its totient is φ = 32012617000.
The previous prime is 32013031409. The next prime is 32013031441. The reversal of 32013031411 is 11413031023.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 11413031023 = 2137 ⋅5340679.
It is a cyclic number.
It is not a de Polignac number, because 32013031411 - 21 = 32013031409 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (32013031441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53155 + ... + 258556.
It is an arithmetic number, because the mean of its divisors is an integer number (8003361456).
Almost surely, 232013031411 is an apocalyptic number.
32013031411 is a deficient number, since it is larger than the sum of its proper divisors (414413).
32013031411 is a wasteful number, since it uses less digits than its factorization.
32013031411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 414412.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 32013031411 its reverse (11413031023), we get a palindrome (43426062434).
It can be divided in two parts, 320130 and 31411, that added together give a triangular number (351541 = T838).
The spelling of 32013031411 in words is "thirty-two billion, thirteen million, thirty-one thousand, four hundred eleven".
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