Base | Representation |
---|---|
bin | 100100011001110010110000… |
… | …0010110110001011100011001 |
3 | 1112222202020022011010020222001 |
4 | 1020303211200112301130121 |
5 | 313432211413212313423 |
6 | 3053003455243401001 |
7 | 124305666246665311 |
oct | 11063454026613431 |
9 | 1488666264106861 |
10 | 320204313401113 |
11 | 93032983229869 |
12 | 2bab58a8823161 |
13 | 109891a2539b6b |
14 | 590dd8598a441 |
15 | 27043b0698cad |
hex | 12339605b1719 |
320204313401113 has 8 divisors (see below), whose sum is σ = 321722392690656. Its totient is φ = 318686239048800.
The previous prime is 320204313401069. The next prime is 320204313401129. The reversal of 320204313401113 is 311104313402023.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 320204313401113 - 241 = 318005290145561 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (320204313411113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 243833598 + ... + 245143288.
It is an arithmetic number, because the mean of its divisors is an integer number (40215299086332).
Almost surely, 2320204313401113 is an apocalyptic number.
It is an amenable number.
320204313401113 is a deficient number, since it is larger than the sum of its proper divisors (1518079289543).
320204313401113 is a wasteful number, since it uses less digits than its factorization.
320204313401113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2468615.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 320204313401113 its reverse (311104313402023), we get a palindrome (631308626803136).
The spelling of 320204313401113 in words is "three hundred twenty trillion, two hundred four billion, three hundred thirteen million, four hundred one thousand, one hundred thirteen".
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