Base | Representation |
---|---|
bin | 11101111001010100… |
… | …010001111001100001 |
3 | 10001212010001120200120 |
4 | 131321110101321201 |
5 | 1011220113133101 |
6 | 22425133110453 |
7 | 2214320415003 |
oct | 357124217141 |
9 | 101763046616 |
10 | 32100130401 |
11 | 12682761099 |
12 | 627a328429 |
13 | 30474ca401 |
14 | 17a732a373 |
15 | c7d1b9b36 |
hex | 779511e61 |
32100130401 has 4 divisors (see below), whose sum is σ = 42800173872. Its totient is φ = 21400086932.
The previous prime is 32100130339. The next prime is 32100130429. The reversal of 32100130401 is 10403100123.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 32100130401 - 27 = 32100130273 is a prime.
It is a super-2 number, since 2×321001304012 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (32100130471) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5350021731 + ... + 5350021736.
It is an arithmetic number, because the mean of its divisors is an integer number (10700043468).
Almost surely, 232100130401 is an apocalyptic number.
It is an amenable number.
32100130401 is a deficient number, since it is larger than the sum of its proper divisors (10700043471).
32100130401 is a wasteful number, since it uses less digits than its factorization.
32100130401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10700043470.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 32100130401 its reverse (10403100123), we get a palindrome (42503230524).
The spelling of 32100130401 in words is "thirty-two billion, one hundred million, one hundred thirty thousand, four hundred one".
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