321014113 has 4 divisors (see below), whose sum is σ = 366873280. Its totient is φ = 275154948.

The previous prime is 321014041. The next prime is 321014159. The reversal of 321014113 is 311410123.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-321014113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (321014173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22929573 + ... + 22929586.

It is an arithmetic number, because the mean of its divisors is an integer number (91718320).

Almost surely, 2^321014113 is an apocalyptic number.

It is an amenable number.

321014113 is a deficient number, since it is larger than the sum of its proper divisors (45859167).

321014113 is an equidigital number, since it uses as much as digits as its factorization.

321014113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45859166.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 321014113 is about 17916.8667182630. The cubic root of 321014113 is about 684.7121620869.

Adding to 321014113 its reverse (311410123), we get a palindrome (632424236).

The spelling of 321014113 in words is "three hundred twenty-one million, fourteen thousand, one hundred thirteen".