Base | Representation |
---|---|
bin | 11101111001011011… |
… | …110011100001001001 |
3 | 10001212020202210201222 |
4 | 131321123303201021 |
5 | 1011221114244423 |
6 | 22425243251425 |
7 | 2214343242233 |
oct | 357133634111 |
9 | 101766683658 |
10 | 32102103113 |
11 | 12683889233 |
12 | 627ab19b75 |
13 | 3047a3b2b2 |
14 | 17a76c1253 |
15 | c7d4593c8 |
hex | 7796f3849 |
32102103113 has 4 divisors (see below), whose sum is σ = 32217995460. Its totient is φ = 31986210768.
The previous prime is 32102103107. The next prime is 32102103151. The reversal of 32102103113 is 31130120123.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 19495978384 + 12606124729 = 139628^2 + 112277^2 .
It is a cyclic number.
It is not a de Polignac number, because 32102103113 - 210 = 32102102089 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 32102103091 and 32102103100.
It is not an unprimeable number, because it can be changed into a prime (32102103713) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57945758 + ... + 57946311.
It is an arithmetic number, because the mean of its divisors is an integer number (8054498865).
Almost surely, 232102103113 is an apocalyptic number.
It is an amenable number.
32102103113 is a deficient number, since it is larger than the sum of its proper divisors (115892347).
32102103113 is a wasteful number, since it uses less digits than its factorization.
32102103113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 115892346.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 32102103113 its reverse (31130120123), we get a palindrome (63232223236).
The spelling of 32102103113 in words is "thirty-two billion, one hundred two million, one hundred three thousand, one hundred thirteen".
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