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32103102113 = 46619688627
BaseRepresentation
bin11101111001011111…
…100111011010100001
310001212022122120002222
4131321133213122201
51011221343231423
622425320520425
72214354602615
oct357137473241
9101768576088
1032103102113
1112684400855
12627b320115
133047ccac14
1417a78a1345
15c7d5a53c8
hex7797e76a1

32103102113 has 4 divisors (see below), whose sum is σ = 32103837360. Its totient is φ = 32102366868.

The previous prime is 32103102013. The next prime is 32103102121. The reversal of 32103102113 is 31120130123.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 32103102113 - 218 = 32102839969 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 32103102091 and 32103102100.

It is not an unprimeable number, because it can be changed into a prime (32103102013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 297695 + ... + 390932.

It is an arithmetic number, because the mean of its divisors is an integer number (8025959340).

Almost surely, 232103102113 is an apocalyptic number.

It is an amenable number.

32103102113 is a deficient number, since it is larger than the sum of its proper divisors (735247).

32103102113 is an equidigital number, since it uses as much as digits as its factorization.

32103102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 735246.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 32103102113 its reverse (31120130123), we get a palindrome (63223232236).

The spelling of 32103102113 in words is "thirty-two billion, one hundred three million, one hundred two thousand, one hundred thirteen".

Divisors: 1 46619 688627 32103102113