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32111013001 = 79406468519
BaseRepresentation
bin11101111001111101…
…110010110010001001
310001212212112110210211
4131321331302302021
51011230404404001
622430202241121
72214512051464
oct357175626211
9101785473724
1032111013001
1112688914381
126281ab61a1
13304983a912
1417a89602db
15c7e119351
hex779f72c89

32111013001 has 4 divisors (see below), whose sum is σ = 32517481600. Its totient is φ = 31704544404.

The previous prime is 32111012971. The next prime is 32111013037. The reversal of 32111013001 is 10031011123.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 32111013001 - 27 = 32111012873 is a prime.

It is a super-2 number, since 2×321110130012 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (32111013071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 203234181 + ... + 203234338.

It is an arithmetic number, because the mean of its divisors is an integer number (8129370400).

Almost surely, 232111013001 is an apocalyptic number.

It is an amenable number.

32111013001 is a deficient number, since it is larger than the sum of its proper divisors (406468599).

32111013001 is an equidigital number, since it uses as much as digits as its factorization.

32111013001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 406468598.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 32111013001 its reverse (10031011123), we get a palindrome (42142024124).

The spelling of 32111013001 in words is "thirty-two billion, one hundred eleven million, thirteen thousand, one".

Divisors: 1 79 406468519 32111013001