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32112003113 = 199971695191
BaseRepresentation
bin11101111010000001…
…100100100000101001
310001212221101202222122
4131322001210200221
51011231133044423
622430235401025
72214523344221
oct357201444051
9101787352878
1032112003113
1112689430253
1262822b3175
133049ac6498
1417a8b3b081
15c7e2628c8
hex77a064829

32112003113 has 8 divisors (see below), whose sum is σ = 33836032320. Its totient is φ = 30391366320.

The previous prime is 32112003107. The next prime is 32112003179. The reversal of 32112003113 is 31130021123.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 32112003113 - 232 = 27817035817 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 32112003091 and 32112003100.

It is not an unprimeable number, because it can be changed into a prime (32112000113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 828653 + ... + 866538.

It is an arithmetic number, because the mean of its divisors is an integer number (4229504040).

Almost surely, 232112003113 is an apocalyptic number.

It is an amenable number.

32112003113 is a deficient number, since it is larger than the sum of its proper divisors (1724029207).

32112003113 is a wasteful number, since it uses less digits than its factorization.

32112003113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1696207.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 32112003113 its reverse (31130021123), we get a palindrome (63242024236).

The spelling of 32112003113 in words is "thirty-two billion, one hundred twelve million, three thousand, one hundred thirteen".

Divisors: 1 19 997 18943 1695191 32208629 1690105427 32112003113